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Matrix (2D array)

Matrix (2D array) problems are a very common category in algorithmic problem solving and competitive programming.

They primarily focus on:

  • navigating rows and columns correctly
  • managing boundaries and indices
  • applying consistent traversal rules
  • performing transformations directly on the input structure

Unlike patterns such as Sliding Window or Kadane’s Algorithm, matrix problems rarely introduce complex algorithmic optimizations.
Instead, they emphasize precision, correctness, and a clear mental model of how the grid is traversed and updated.

Once the main traversal or transformation pattern is identified, the solution is usually straightforward to implement and runs in linear time with respect to the number of cells.

Traversal Patterns

Most matrix problems are not about complex algorithms, but about how you move inside the grid.
Understanding traversal patterns is the key to solving 2D array exercises correctly and cleanly.

Row-wise Traversal

The simplest pattern scans the matrix row by row, from left to right.

for (let r = 0; r < rows; r++) {
  for (let c = 0; c < cols; c++) {
    // process matrix[r][c]
  }
}

This traversal is commonly used when:

  • checking row-based constraints (e.g. Sudoku rows)
  • aggregating values row by row
  • performing straightforward transformations

Column-wise Traversal

This pattern scans the matrix column by column, from top to bottom.

for (let c = 0; c < cols; c++) {
  for (let r = 0; r < rows; r++) {
    // process matrix[r][c]
  }
}

It is useful when:

  • validating column-based rules,
  • computing column aggregates,
  • or when the problem explicitly refers to columns.

Directional Traversal

Directional traversal moves through the matrix following a specific direction. It is often used as a building block for more complex patterns.

/// left to right
for (let c = left; c <= right; c++) {
  // process matrix[top][c]
}

/// top to bottom
for (let r = top; r <= bottom; r++) {
  // process matrix[r][right]
}

/// right to left
for (let c = right; c >= left; c--) {
  // process matrix[bottom][c]
}

/// bottom to top
for (let r = bottom; r >= top; r--) {
  // process matrix[r][left]
}

Spiral Traversal

Spiral traversal processes the matrix layer by layer, shrinking its boundaries after each full cycle.

let top = 0;
let bottom = rows - 1;
let left = 0;
let right = cols - 1;

while (top <= bottom && left <= right) {
  // left → right
  for (let c = left; c <= right; c++) {
    // process matrix[top][c]
  }
  top++;

  // top → bottom
  for (let r = top; r <= bottom; r++) {
    // process matrix[r][right]
  }
  right--;

  if (top <= bottom) {
    // right → left
    for (let c = right; c >= left; c--) {
      // process matrix[bottom][c]
    }
    bottom--;
  }

  if (left <= right) {
    // bottom → top
    for (let r = bottom; r >= top; r--) {
      // process matrix[r][left]
    }
    left++;
  }
}

Simulation-Based Traversal

Some problems require updating the matrix over multiple steps rather than producing a single traversal order.

Typical characteristics:

  • the next state depends on neighboring cells,
  • in-place updates may require temporary markers,
  • or a copy of the matrix to preserve the previous state.

Time & Space Complexity

Matrix problems are usually bounded by the size of the grid itself.
In most cases, the complexity is dictated by how many times each cell is visited.

Below is a summary of the most common patterns and their complexities.

Pattern / OperationTime ComplexitySpace Complexity
Full matrix traversalO(m×n)O(m × n)O(1)O(1)
Row-wise / column-wise scanO(m×n)O(m × n)O(1)O(1)
Spiral traversalO(m×n)O(m × n)O(1)O(1)
In-place matrix rotationO(m×n)O(m × n)O(1)O(1)
Validation (rows + cols + boxes)O(m×n)O(m × n)O(1)O(1)
Simulation with temporary stateO(m×n)O(m × n)O(m×n)O(m × n)

It is important to note that:

  • Most matrix problems require visiting every cell at least once, making O(m × n) unavoidable.
  • Well-designed solutions avoid extra data structures and work in-place whenever possible.
  • Additional space is only required when:
    • previous state must be preserved (e.g. simulations),
    • temporary markers or auxiliary grids are needed.

Understanding these constraints helps focus on correct traversal and boundary handling, rather than over-optimizing time complexity.

Exercises

ProblemTechniqueSolution
Spiral MatrixDirectional traversal + boundary shrinkSolution
Rotate ImageIn-place transpose + row reversalSolution
Set Matrix ZeroesIn-place markers (first row/column)Solution
Valid SudokuConstraint validation (rows, columns, boxes)Solution
Game of LifeIn-place state encoding / simulationSolution
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